sin x cos x sin x

Theother three functions are the secant, cosecant, and cotangent - these are the reciprocal of the sine, cosine and tangent respectively. This is important, because the notation sin-1 (x) is used to indicate the inverse sine function, or arc sine - that is, the angle whose sine Applythe reciprocal identity to sec(x) sec ( x). Write −cos(x) - cos ( x) as a fraction with denominator 1 1. Add fractions. Tap for more steps Multiply −cos(x)cos(x) - cos ( x) cos ( x). Apply pythagorean identity. Rewrite sin2 (x) cos(x) sin 2 ( x) cos ( x) as sin(x)tan(x) sin ( x) tan ( x). Because the two sides have been shown to be Theangle sum trigonometric identity in sine function is written in several forms but it is popularly expressed in the following three forms. ( 1). sin ( A + B) = sin A cos B + cos A sin B. ( 2). sin ( x + y) = sin x cos y + cos x sin y. ( 3). sin ( α + β) = sin α cos β + cos α sin β. Thisproblem has been solved! See the answer. Prove the identity. sin (x − y + z) = sin (x) cos (y) cos (z) − cos (x) sin (y) cos (z) + cos (x) cos (y) sin (z) + sin (x) sin (y) sin (z) Regroup, and apply the Addition and Subtraction Formulas as needed. sin (x − y + z) = sin (x − y) + z = Incorrect: Your answer is incorrect. cos (z App Vay Tiền Nhanh. 2 Answers Please see two possibilities below and another in a separate answer. Explanation Using Pythagorean Identity sin^2x+cos^2x=1, so cos^2x = 1-sin^2x cosx = +- sqrt 1-sin^2x sinx + cosx = sinx +- sqrt 1-sin^2x Using complement / cofunction identity cosx = sinpi/2-x sinx + cosx = sinx + sinpi/2-x I've learned another way to do this. Thanks Steve M. Explanation Suppose that sinx+cosx=Rsinx+alpha Then sinx+cosx=Rsinxcosalpha+Rcosxsinalpha =Rcosalphasinx+Rsinalphacosx The coefficients of sinx and of cosx must be equal so Rcosalpha = 1 Rsinalpha=1 Squaring and adding, we get R^2cos^2alpha+R^2sin^2alpha = 2 so R^2cos^2alpha+sin^2alpha = 2 R = sqrt2 And now cosalpha = 1/sqrt2 sinalpha = 1/sqrt2 so alpha = cos^-11/sqrt2 = pi/4 sinx+cosx = sqrt2sinx+pi/4 Impact of this question 208126 views around the world

sin x cos x sin x